And how many of the higher values can be swapped to substitute how many of the smaller notes. For example, replacing a 1 with a 5 saves you 4 notes, 5 with a 10 will allow you to save on 5 additional 1 Rupee notes, replacing a 5 with a 20 yields 15, etc. If you then target a factor of 50 total notes, then it becomes a matter of simply repeating
I’m therefore going to create a million pounds out of £20 notes. To do this I need to know the dimensions of the £20 bank note. Each one is 149x80mm with a thickness of 0.113mm. A stack of 100 notes with a value of £2000 will therefore be just 11.3mm high. Or 1.13cm if you prefer. Here is £2000 with some mystery legs to give you a sense
Enter the amount: 5454 Total number of notes: 2000 = 2 500 = 2 200 = 2 100 = 0 50 = 1 20 = 0 10 = 0 5 = 0 2 = 2 1 = 0 Conclusion. I hope after going through this post, you understand how to count total numbers of notes in the given amount using C++ Programming language.
If amount is greater than 500 then, divide amount by 500 to get maximum 500 notes required. Store the division result in some variable say note500 = amt / 500;. After division, subtract the resultant amount of 500 notes from original amount. Perform amt = amt - (note500 * 500). Repeat above step, for each note 200, 100, 50, 20, 10, 5, 2 and 1.
The RBI had previously announced its plan to phase out the Rs 2,000 note. NEW DELHI: Reserve Bank Governor Shaktikanta Das on Friday said Rs 2,000 denomination notes are coming back and only Rs
To cope with an influx of 2,000-rupee notes, he has posted signs warning customers not to fill their tanks with 50 rupees, or about 60 cents, worth of gas and expect to receive change..